Abstract
We prove that for every automata algebra of exponential growth the associated Lie algebra contains a free subalgebra. For n ≥ 1, let L n+2 be a Lie algebra with generators x1,⋯, x n+2 and the following relations: for k ≤ n, any commutator (with any arrangement of brackets) of length k which consists of fewer than k different symbols from {x1,⋯, xn+2} is zero. As an application of this result about automata algebras, we prove that L n+2 contains a free subalgebra for every n ≥ 1. We also prove the similar result about groups defined by commutator relations. Let Gn+2 be a group with n + 2 generators y1,⋯, yn+2 and the following relations: for k ≤ n, any left-normalized commutator of length k which consists of fewer than k different symbols from {y1,⋯, yn+2} is trivial. Then the group Gn+2 contains a 2-generated free subgroup. The main technical tool is combinatorics of words, namely combinatorics of periodical sequences and period switching.
| Original language | English |
|---|---|
| Pages (from-to) | 15-29 |
| Number of pages | 15 |
| Journal | Groups, Geometry, and Dynamics |
| Volume | 4 |
| Issue number | 1 |
| DOIs | |
| State | Published - 2010 |
Keywords
- Automata algebra
- Free group
- Lie algebra
- Nilpotency
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