An Example of two Cardinals that are Equivalent in the n-Order Logic and not Equivalent in the (n + 1)-Order Logic

V. A. Bragin; E. I. Bunina

doi:10.1007/s10958-014-2002-0

An Example of two Cardinals that are Equivalent in the n-Order Logic and not Equivalent in the (n + 1)-Order Logic

V. A. Bragin
, E. I. Bunina

Lomonosov Moscow State University

Research output: Contribution to journal › Article › peer-review

1 Scopus citations

Abstract

It is proved that the property of two models to be equivalent in the nth order logic is definable in the (n + 1)th order logic. Basing on this fact, there is given an (nonconstructive) "example" of two n-order equivalent cardinal numbers that are not (n + 1)-order equivalent.

Original language	English
Pages (from-to)	431-437
Number of pages	7
Journal	Journal of Mathematical Sciences (United States)
Volume	201
Issue number	4
DOIs	https://doi.org/10.1007/s10958-014-2002-0
State	Published - Sep 2014
Externally published	Yes

Access to Document

10.1007/s10958-014-2002-0

Cite this

@article{48ad8e719f7041cd8edc14ec376ca18e,

title = "An Example of two Cardinals that are Equivalent in the n-Order Logic and not Equivalent in the (n + 1)-Order Logic",

abstract = "It is proved that the property of two models to be equivalent in the nth order logic is definable in the (n + 1)th order logic. Basing on this fact, there is given an (nonconstructive) {"}example{"} of two n-order equivalent cardinal numbers that are not (n + 1)-order equivalent.",

author = "Bragin, \{V. A.\} and Bunina, \{E. I.\}",

year = "2014",

month = sep,

doi = "10.1007/s10958-014-2002-0",

language = "אנגלית",

volume = "201",

pages = "431--437",

journal = "Journal of Mathematical Sciences (United States)",

issn = "1072-3374",

publisher = "Springer",

number = "4",

}

TY - JOUR

T1 - An Example of two Cardinals that are Equivalent in the n-Order Logic and not Equivalent in the (n + 1)-Order Logic

AU - Bragin, V. A.

AU - Bunina, E. I.

PY - 2014/9

Y1 - 2014/9

N2 - It is proved that the property of two models to be equivalent in the nth order logic is definable in the (n + 1)th order logic. Basing on this fact, there is given an (nonconstructive) "example" of two n-order equivalent cardinal numbers that are not (n + 1)-order equivalent.

AB - It is proved that the property of two models to be equivalent in the nth order logic is definable in the (n + 1)th order logic. Basing on this fact, there is given an (nonconstructive) "example" of two n-order equivalent cardinal numbers that are not (n + 1)-order equivalent.

UR - https://www.scopus.com/pages/publications/84906091076

U2 - 10.1007/s10958-014-2002-0

DO - 10.1007/s10958-014-2002-0

M3 - ???researchoutput.researchoutputtypes.contributiontojournal.article???

AN - SCOPUS:84906091076

SN - 1072-3374

VL - 201

SP - 431

EP - 437

JO - Journal of Mathematical Sciences (United States)

JF - Journal of Mathematical Sciences (United States)

IS - 4

ER -

An Example of two Cardinals that are Equivalent in the n-Order Logic and not Equivalent in the (n + 1)-Order Logic

Abstract

Access to Document

Other files and links

Fingerprint

Cite this